就这段matlab，用C#写起码要五倍的代码量吧？
R_ice=zeros(size(Branch,1),t);
LI=zeros(size(Branch,1),t);
for i=1:size(Branch,1)
for j=1:t
if YX_z(i,j)~=0
R_ice(i,j)=R_ice(i,(j-1))+0.25*sqrt(DY^2+((3.6*v_w(i,j)*0.067*DY^0.846))^2)/(0.9*3.1415926);
R_ice(i,j:t)=R_ice(i,j);
LI(i,j)=0.0098*0.9*pi*(D+R_ice(i,j))*R_ice(i,j);
LW(i,j)=6.964*0.001*(v_w(i,j)^2)*(D+2*R_ice(i,j));
LWI(i,j)=sqrt(LI(i,j)^2+LW(i,j)^2);
if LWI(i,j)<15
P(i,j)=0;
else if LWI(i,j)<=75
P(i,j)=exp((0.6931*(LWI(i,j)-15))/(75-15))-1;
else
P(i,j)=1;
end
end
else
P(i,j)=0;
end
end
end
for i=1:size(Branch,1)
for j=1:t
P_z(i,j)=1-(1-P(i,j))^YX_z(i,j);
end
end
a_pole=0.01;
b_pole=0.8;
a_plot=zeros(size(Branch,1),t);
for i=1:size(Branch,1)
for j=1:t
if LI(i,j)~=0
a_plot(i,j)=LI(i,j)*((l_1+l_2)/2+(F11*h_1/(LI(i,j)*l_1))+(F12*h_2/(LI(i,j)*l_2)));
end
end
end
for i=1:size(Branch,1)
for j=1:t
P_ganta(i,j)=a_pole*exp(a_plot(i,j)/(b_pole*M_pole));
end
end
nita=[0.05,0.1,0.15,0.2];
T0=32806;
l=500;
n=3;
g=9.8;
seita=pi/18;
seita0=pi/6;
S=23746;
f=zeros(size(Branch,1),t);
Z=zeros(size(Branch,1),t);
for i=1:size(Branch,1)
for j=1:t
if LI(i,j)~=0
f(i,j)=(1/(2*l))*sqrt(T0/LI(i,j));
Z(i,j)=nita(1)*v_w(i,j)*sind(beta(i))/(f(i,j)*2);
end
end
end
for i=1:size(Branch,1)
for j=1:t
if Z(i,j)>=5.5
pwd(i,j)=1;
elseif Z(i,j)>3
pwd(i,j)=(Z(i,j)-3)/(5.5-3);
else
pwd(i,j)=0;
end
end
end
for j=1:1:t
for i=1:size(Branch,1)
p_zong(i,j)=1-(1-pwd(i,j))*(1-P_ganta(i,j))*(1-P_z(i,j));
end
end